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4800th term
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Q. The 4800th term of the sequence : 1,3,3,3,5,5,5,5,5,7,7,7,7,7,7,7,9……??
chk the no. of terms of each number
1 is 1 time ,
3 is 3 times ,
5 is 5 times ..
so start calculating the no. of terms somewhere less than 4800
you will get it by adding 1+3+5 +….. +2n-1 <= 4800
1+3+5+…+2n-1 is sum of odd numbers and is equal to n2.
so n2 <= 4800.
n = 69 since 692 = 4761
Hence next term i.e. 4762th term to 4900th term is is 70th odd number i.e 70×2-1 = 139 Ans
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